1) Nucleus of frozen ether.-----[Return home ]

A. Sphericity of the equiphase surfaces.

At a given time, in the rest frame, if we consider the divergent wave or the convergent one, a particular phase value of these waves determines a surface (equiphase surface) which, for example, for the convergent wave is:

This surface is always spherical like we may be easily convince of it, with t=0 and by a few geometric or algebraic transformations.

B. Existence of a spherical (or ellipsoidal) nucleus of frozen ether.

When the electron is at rest in the rest frame, the convergent wave has an equation of the form A=A(r) sin2.pi(t+r/c) where the amplitude A(r) is still unknown, but clearly must increase of intensity towards the center of the electron, at the first sight in 1/r to permit the full wave to be solution of the wave equation: Laplacian A-[1/cc]ddA/dtdt=0

Thus, for a particular weak value of r, the intensity will be so high that the instantenous pressure may lead the ether particules in direct contact and to form an imcompressible medium (frozen ether) able to reflect the wave.

I cannot decide, if the center of the electron is full of an imcompressible medium, but we have certainly a spherical shell (for the electron at rest) which reflect he convergent wave to produce the divergent one.

Later, we will see with the theory, that if the the radius of the electron at rest is Ro, the electron in motion has an ellipsoidal nucleus with the main axis of values: Ro and Ro.sqrt(1-bb) with b=v/c. A contraction in the motion direction.

Obviously the nucleus in motion is not concerned by any friction with the particules of the ether. It is because when the electron is in motion, it is the wave structure which builds the nucleus from the ether in frozing it in front of it. The same way, at the bottom, the nucleus melts down as quickly as its velocity.

The nucleus is thus continuously replaced by new ether particules.

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